Chapter 4. The Second Law of Thermodynamics
4.3 Refrigerators and Heat Pumps
Learning Objectives
By the end of this section, you will be able to:
- Describe a refrigerator and a heat pump and list their differences
- Calculate the performance coefficients of simple refrigerators and heat pumps
The cycles we used to describe the engine in the preceding section are all reversible, so each sequence of steps can just as easily be performed in the opposite direction. In this case, the engine is known as a refrigerator or a heat pump, depending on what is the focus: the heat removed from the cold reservoir or the heat dumped to the hot reservoir. Either a refrigerator or a heat pump is an engine running in reverse. For a refrigerator, the focus is on removing heat from a specific area. For a heat pump, the focus is on dumping heat to a specific area.
We first consider a refrigerator (Figure 4.6). The purpose of this engine is to remove heat from the cold reservoir, which is the space inside the refrigerator for an actual household refrigerator or the space inside a building for an air-conditioning unit.

A refrigerator (or heat pump) absorbs heat

The effectiveness or coefficient of performance
Note that we have used the condition of energy conservation,
The effectiveness or coefficient of performance
Once again, we use the energy conservation condition
Summary
- A refrigerator or a heat pump is a heat engine run in reverse.
- The focus of a refrigerator is on removing heat from the cold reservoir with a coefficient of performance
- The focus of a heat pump is on dumping heat to the hot reservoir with a coefficient of performance
Conceptual Questions
If the refrigerator door is left open, what happens to the temperature of the kitchen?
Show Solution
The temperature increases since the heat output behind the refrigerator is greater than the cooling from the inside of the refrigerator.
Is it possible for the efficiency of a reversible engine to be greater than 1.0? Is it possible for the coefficient of performance of a reversible refrigerator to be less than 1.0?
Problems
A refrigerator has a coefficient of performance of 3.0. (a) If it requires 200 J of work per cycle, how much heat per cycle does it remove the cold reservoir? (b) How much heat per cycle is discarded to the hot reservoir?
Show Solution
a. 600 J; b. 800 J
During one cycle, a refrigerator removes 500 J from a cold reservoir and discharges 800 J to its hot reservoir. (a) What is its coefficient of performance? (b) How much work per cycle does it require to operate?
If a refrigerator discards 80 J of heat per cycle and its coefficient of performance is 6.0, what are (a) the quantity off heat it removes per cycle from a cold reservoir and (b) the amount of work per cycle required for its operation?
Show Solution
a. 69 J; b. 11 J
A refrigerator has a coefficient of performance of 3.0. (a) If it requires 200 J of work per cycle, how much heat per cycle does it remove the cold reservoir? (b) How much heat per cycle is discarded to the hot reservoir?
Glossary
- coefficient of performance
- measure of effectiveness of a refrigerator or heat pump
- heat pump
- device that delivers heat to a hot reservoir
- refrigerator
- device that removes heat from a cold reservoir
Licenses and Attributions
Refrigerators and Heat Pumps. Authored by: OpenStax College. Located at: https://openstax.org/books/university-physics-volume-2/pages/4-3-refrigerators-and-heat-pumps. License: CC BY: Attribution. License Terms: Download for free at https://openstax.org/books/university-physics-volume-2/pages/1-introduction